The distance of the point $(3,4)$ from the line $3x + 4y - 5 = 0$ is:
- 5
- 4
- 2
- $\tfrac{20}{7}$
Show answer and solution
Correct answer: B. 4
We have d = |3·3 + 4·4 − 5| / √(3²+4²).
That is d = |9+16−5|/5.
That is d = 20/5.
So d = 4.
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Correct answer: B. 4
Correct answer: B. 6
Correct answer: D. $-\tfrac13$
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