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The distance of the point $(3,4)$ from the line $3x + 4y - 5 = 0$ is:
A5
B4
C2
D$\tfrac{20}{7}$
Answer & Solution
Correct answer: B. 4
d = |3·3 + 4·4 − 5| / √(3²+4²) = |9+16−5|/5 = 20/5 = 4.
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