alleryThe distance of the point $(3,4)$ from the line $3x + 4y - 5 = 0$ is:
A5
B4
C2
D$\tfrac{20}{7}$
Answer & Solution
Correct answer: B. 4
We have d = |3·3 + 4·4 − 5| / √(3²+4²).
That is d = |9+16−5|/5.
That is d = 20/5.
So d = 4.
Keep practising Straight Lines and Conic Sections
Browse all Straight Lines and Conic Sections questions for GRE, or explore more Mathematics topics.
Related questions
The line 3x − 4y + 12 = 0 cuts the y-axis atThe intercept form of the equation of a line making intercepts a and b on the x- and y-axeThe distance between the parallel lines 3x + 4y = 7 and 3x + 4y = 12 isThe angle θ between two lines with slopes m₁ and m₂ satisfiesThe distance from the point (0, 0) to the line 3x + 4y − 25 = 0 isEquation of the line passing through (3, 4) and parallel to the line 2x − 3y = 5 isThe equation of the line passing through (2, −1) with slope 3 isThe slope-intercept form y = mx + c of the line 3x + 4y = 8 gives a slope of