Home › IPMAT Indore › mathematics › straight_lines › The distance between the parallel lines 3x + 4y …
The distance between the parallel lines 3x + 4y = 7 and 3x + 4y = 12 is
A1
B2
C5
D1/5
Answer & Solution
Correct answer: A. 1
d = |C₁ − C₂| / √(A² + B²) = |12 − 7|/√(9 + 16) = 5/5 = 1 unit.
Related questions
The line 3x − 4y + 12 = 0 cuts the y-axis atThe intercept form of the equation of a line making intercepts a and b on the x- and y-axeThe angle θ between two lines with slopes m₁ and m₂ satisfiesThe distance from the point (0, 0) to the line 3x + 4y − 25 = 0 isEquation of the line passing through (3, 4) and parallel to the line 2x − 3y = 5 isThe equation of the line passing through (2, −1) with slope 3 isThe slope-intercept form y = mx + c of the line 3x + 4y = 8 gives a slope ofThe slope of the line joining (2, 3) and (5, 11) is