The distance between the parallel lines 3x + 4y = 7 and 3x + 4y = 12 is
A1
B2
C5
D1/5
Answer & Solution
Correct answer: A. 1
d = |C₁ − C₂| / √(A² + B²) = |12 − 7|/√(9 + 16) = 5/5 = 1 unit.
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