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Equation of the line passing through (3, 4) and parallel to the line 2x − 3y = 5 is
A2x − 3y − 6 = 0
B3x − 2y + 1 = 0
C2x + 3y = 18
D2x − 3y + 6 = 0
Answer & Solution
Correct answer: D. 2x − 3y + 6 = 0
Slope of 2x − 3y = 5 is 2/3. Point-slope through (3, 4): y − 4 = (2/3)(x − 3). Clearing fractions: 3y − 12 = 2x − 6 ⇒ 2x − 3y + 6 = 0. Verify at (3, 4): 6 − 12 + 6 = 0.
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