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In triangle PQR, S and T are points on PQ and PR respectively. ST is parallel to QR. If PS = 3, SQ = 6 and PT = 4, then PR equals
A8
B10
C14
D12
Answer & Solution
Correct answer: D. 12
1. By BPT, PS/SQ = PT/TR. So 3/6 = 4/TR, giving TR = 8.
2. PR = PT + TR = 4 + 8.
3. Hence PR = 12.
_Source: NCERT Class 10 Mathematics, Ch 6 "Triangles", §6.3_
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