alleryIn an isosceles triangle ABC with AB = AC = 13 cm and BC = 10 cm, the altitude from A to BC is
A8 cm
B10 cm
C15 cm
D12 cm
Answer & Solution
Correct answer: D. 12 cm
1. Foot of altitude D bisects BC (isosceles), so BD = 5.
2. By Pythagoras in triangle ABD: AD squared = 13 squared minus 5 squared = 169 minus 25 = 144.
3. AD = 12 cm.
_Source: syllabus Mathematics, Ch 6 "Triangles", §6.5_
Keep practising Triangles and Circles
Browse all Triangles and Circles questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Two circles touch each other externally at P. A common tangent at P meets another common tIn a circle, two chords AB and CD intersect inside at P. If AP × PB = 8 and CP = 4, then PA point P is 25 cm away from the centre O of a circle and the tangent PT to the circle is Two parallel tangents are drawn to a circle of radius 8 cm. The distance between them isA tangent at point P of a circle of radius 5 cm is parallel to a chord 8 cm long. The distA circle touches all four sides of a quadrilateral ABCD with AB = 6, BC = 7, CD = 4. Then PA and PB are tangents from a point P to a circle. If angle APB = 90 degrees, the radius aA line drawn through the centre of a circle to bisect a chord is