For a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order of acceleration (fastest first):
- All equal
- Sphere > Disc > Hoop (smaller I/MR² is faster)
- Disc > Sphere > Hoop
- Hoop > Disc > Sphere
Show answer and solution
Correct answer: B. Sphere > Disc > Hoop (smaller I/MR² is faster)
**Acceleration in rolling:** a = g sin theta / (1 + I/(MR²)).
For sphere I/MR² = 2/5 (smallest)
disc 1/2; hoop 1. So sphere is fastest, hoop slowest.
Independent of mass and radius!