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AP Intermediate 1st Year Chemical Bonding and Molecular Structure — practice questions

Explore 70 free Chemical Bonding and Molecular Structure questions in AP Intermediate 1st Year Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Chemical Bonding and Molecular Structure questions and exercises with answers

Showing questions 1–30 of 70.

As per your syllabus, which species violates the octet rule because of an ODD electron count?Read the answer and worked solution →As per your syllabus, the H-O-H BOND ANGLE in water molecule is which value?Read the answer and worked solution →As per your syllabus, the order of repulsion between electron pairs in VSEPR is which?Read the answer and worked solution →As per your syllabus, what is the geometry of a molecule of type AB₅ with NO lone pairs on the central atom (e.g. PCl₅)?Read the answer and worked solution →As per your syllabus, what is the geometry of a molecule of type AB₆ with NO lone pairs (e.g. SF₆)?Read the answer and worked solution →As per your syllabus, the shape of XeF₄ (4 bp + 2 lp on Xe) is which?Read the answer and worked solution →As per your syllabus, BCl₃ has its boron sp² hybridised. What is the molecular geometry + bond angle?Read the answer and worked solution →As per your syllabus, in sp³ hybridisation (e.g. CH₄), each hybrid has 25% s + 75% p character. What is the H-C-H angle and shape?Read the answer and worked solution →As per your syllabus, the C=C double bond consists of what, and each carbon's hybridisation is which?Read the answer and worked solution →As per your syllabus, PCl₅ uses what hybridisation, and gives what geometry?Read the answer and worked solution →As per your syllabus, SF₆ uses what hybridisation, and gives what geometry?Read the answer and worked solution →As per your syllabus, the MOT bond order of oxygen is computed as which?Read the answer and worked solution →As per your syllabus, the magnitude of hydrogen bonding depends on the physical state of the compound — and is MAXIMUM in which state?Read the answer and worked solution →The shape of the methane (CH$_4$) molecule is:Read the answer and worked solution →The hybridisation of carbon in ethyne (HC$\equiv$CH) is:Read the answer and worked solution →An IONIC bond is formed by:Read the answer and worked solution →The bond in N2 (nitrogen molecule) is a:Read the answer and worked solution →In the H3O+ ion, the bond between H+ and H2O is a:Read the answer and worked solution →The geometry of CH4 (methane) as predicted by VSEPR is:Read the answer and worked solution →The hybridisation of carbon in C2H4 (ethylene, with a C=C double bond) is:Read the answer and worked solution →Molecular Orbital Theory uniquely EXPLAINS why O2 is:Read the answer and worked solution →The molecule CO2 has zero net DIPOLE MOMENT because:Read the answer and worked solution →NEET · Chemistry · Chemical Bonding · Ionic or CovalentRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Geometry of MoleculeRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · HybridisationRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Tap Polar MoleculesRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Bond Order — Gap FillRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Sigma or Pi BondRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Equation Balance — Combustion of MethaneRead the answer and worked solution →NEET · Chemistry · Chemical Bonding · Bond LengthRead the answer and worked solution →

Worked practice questions

As per your syllabus, which species violates the octet rule because of an ODD electron count?

  1. CH₄ and C₂H₆
  2. BeCl₂
  3. H₂O and NH₃
  4. NO and NO₂
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Correct answer: D. NO and NO₂

As per your syllabus, NO + NO₂ have odd total e⁻, so octet on every atom is impossible.

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As per your syllabus, the H-O-H BOND ANGLE in water molecule is which value?

  1. 109.5°
  2. 180°
  3. 104.5°
  4. 120°
Show answer and solution

Correct answer: C. 104.5°

As per your syllabus, + 4.6.1, H₂O is sp³ with two lone pairs → angle compressed to 104.5° (from 109.5°).

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As per your syllabus, the order of repulsion between electron pairs in VSEPR is which?

  1. bp–bp > lp–lp > lp–bp
  2. All three are equal
  3. lp–bp > lp–lp > bp–bp
  4. lp–lp > lp–bp > bp–bp
Show answer and solution

Correct answer: D. lp–lp > lp–bp > bp–bp

As per your syllabus, lp-lp largest (lone pair more diffuse), then lp-bp, then bp-bp. Explains bond-angle compressions.

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