The hybridisation of carbon in ethyne (HC$\equiv$CH) is:
Asp, giving a linear molecule with $180^\circ$ bond angle
Bsp$^2$, giving a trigonal planar shape at carbon centre
Csp$^3$, giving the tetrahedral shape around the carbon
Dsp$^3$d, with five bonds around each of the carbons
Answer & Solution
Correct answer: A. sp, giving a linear molecule with $180^\circ$ bond angle
Triple bond carbon is sp hybridised; ethyne is linear.
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