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As per your syllabus, the MOT bond order of oxygen is computed as which?
A0
B½(10 − 6) = 2 (a double bond)
C3
D½(6 − 10) = −2
Answer & Solution
Correct answer: B. ½(10 − 6) = 2 (a double bond)
As per your syllabus, O₂: N_b = 10, N_a = 6, b.o.
= 2 — consistent with O=O double bond.
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