alleryThe hybridisation of carbon in C2H4 (ethylene, with a C=C double bond) is:
Asp² (trigonal planar, 120°)
Bsp (linear, 180°)
Csp³ (tetrahedral, 109.5°)
Dsp³d (trigonal bipyramidal)
Answer & Solution
Correct answer: A. sp² (trigonal planar, 120°)
Each C in ethylene forms 3 sigma bonds (to other C + 2 H atoms) + 1 pi bond.
So 3 sigma → sp² hybridisation.
**Geometry:** trigonal planar at each C; bond angles ~120°.
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