What energy photon is emitted when a hydrogen electron falls from n = 3 to n = 2?
A10.2 eV
B1.89 eV
C3.40 eV
D1.51 eV
Answer & Solution
Correct answer: B. 1.89 eV
E3 - E2 = -1.51 eV - (-3.40 eV) = 1.89 eV.
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