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A hydrogen electron falls from n = 3 to n = 2. What photon energy is emitted?
A1.51 eV
B1.89 eV
C3.40 eV
D10.2 eV
Answer & Solution
Correct answer: B. 1.89 eV
The photon carries E3 - E2 = -1.51 eV minus -3.40 eV, which is 1.89 eV.
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