For a sinusoidal voltage v(t) = V_m sin(ωt), the RMS value is:
AV_m
BV_m / √2 ≈ 0.707 V_m
CV_m × √2
DV_m / 2
Answer & Solution
Correct answer: B. V_m / √2 ≈ 0.707 V_m
**RMS (root mean square) of sin:** V_rms = V_m/√2. Equivalent DC voltage that delivers same power.
**Indian mains:** V_rms = 230 V
→ V_peak = 230√2 ≈ 325 V. Average over full cycle of pure sin is zero
RMS is the meaningful 'effective' value.
Keep practising Electrical Circuits & Fundamentals
Browse all Electrical Circuits & Fundamentals questions for GATE EE, or explore more Electrical Engineering topics.
Related questions
Drag each behaviour to its componentKnock out the false AC claimsFor sinusoidal v(t) = V_m cos(ωt), peak-to-peak value:Two-wattmeter method measures 3-phase power. Total power:RL time constant:Energy density in magnetic field B is:In a 3-phase transmission line, line voltage rms is 415 V. Phase voltage (Y/star) is:Force on a current-carrying conductor of length l in magnetic field B (perpendicular):