alleryStart learning →Power dissipated in a resistor under DC:
AV + I
BP = VI = I²R = V²/R
CV × I
DV/I
Answer & Solution
Correct answer: B. P = VI = I²R = V²/R
**DC resistor power:** P = VI.
Using Ohm's law (V=IR), three forms: VI, I²R, V²/R. Always positive (resistor dissipates energy as heat). Energy: E = P × t.
Keep practising Electrical Circuits & Fundamentals
Browse all Electrical Circuits & Fundamentals questions for GATE EE, or explore more Electrical Engineering topics.
Related questions
Drag each behaviour to its componentKnock out the false AC claimsFor sinusoidal v(t) = V_m cos(ωt), peak-to-peak value:Two-wattmeter method measures 3-phase power. Total power:RL time constant:Energy density in magnetic field B is:In a 3-phase transmission line, line voltage rms is 415 V. Phase voltage (Y/star) is:Force on a current-carrying conductor of length l in magnetic field B (perpendicular):