The BALMER series of hydrogen corresponds to electron transitions ending at:
A$n = 1$ (Lyman series, UV)
B$n = 3$ (Paschen series, IR)
C$n = 4$ (Brackett series, IR)
D$n = 2$ (Balmer series, visible)
Answer & Solution
Correct answer: D. $n = 2$ (Balmer series, visible)
Balmer series: transitions ending at n = 2, in the visible region (the only visible H series). Lyman → n = 1 (UV). Paschen → n = 3, Brackett → n = 4, Pfund → n = 5 (all IR).
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