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Heisenberg's uncertainty principle is most accurately stated as:

A$\Delta x \cdot \Delta p = 0$ (perfect precision)
B$\Delta x + \Delta p < h/2$ (sum bound)
C$\Delta x \cdot \Delta p \geq h/(4\pi)$ (product bound)
D$\Delta x = \Delta p$ (equal uncertainties)
Answer & Solution
Correct answer: C. $\Delta x \cdot \Delta p \geq h/(4\pi)$ (product bound)
**Heisenberg:** Δx × Δp ≥ h/(4π). Product of position and momentum uncertainties has a MINIMUM. So we cannot know both with arbitrary precision. Crucial for quantum mechanics.
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