Home › JEE Advanced › Chemistry › d- and f-Block Elements › Magnetic susceptibility of Fe³⁺ vs Fe²⁺ in high-…
Magnetic susceptibility of Fe³⁺ vs Fe²⁺ in high-spin complexes:
AFe³⁺ (d⁵, 5 unpaired) > Fe²⁺ (d⁶, 4 unpaired)
BBoth zero
CEqual
DFe²⁺ greater
Answer & Solution
Correct answer: A. Fe³⁺ (d⁵, 5 unpaired) > Fe²⁺ (d⁶, 4 unpaired)
Fe³⁺ high spin: d⁵, μ = 5.92 BM. Fe²⁺ high spin: d⁶, t₂g⁴ e_g², 4 unpaired, μ = 4.90 BM. Hence Fe³⁺ more paramagnetic. Useful for distinguishing Fe oxidation states magnetically.
Related questions
Which of the following coordination compounds shows OPTICAL ISOMERISM?The HEXACYANIDOFERRATE(II) ion $[\mathrm{Fe(CN)_6}]^{4-}$ contains iron in oxidation state$[\mathrm{Ni(CO)_4}]$ is tetrahedral and diamagnetic. The oxidation state of nickel in thiCoordination compounds of transition metals are often COLOURED. CFT explains this colour aWhich of the following best states the CHELATE EFFECT?Cis-trans isomerism is observed in$[\mathrm{Fe(CN)_6}]^{4-}$ has $\mathrm{CN^-}$ ligands, which are STRONG-FIELD ligands. ThIn CRYSTAL FIELD THEORY (CFT) for an OCTAHEDRAL complex, the five degenerate d-orbitals of