Practice free →
HomeJEE MainMathematicsConic Sections › Equation of circle with center (h, k) and radius…

Equation of circle with center (h, k) and radius r:

Ax + y = r
Bx² + y² = h
Cx² = r
D(x - h)² + (y - k)² = r²
Answer & Solution
Correct answer: D. (x - h)² + (y - k)² = r²
Standard equation of circle. For center (0,0): x² + y² = r². General second-degree: x² + y² + 2gx + 2fy + c = 0, center (-g, -f), radius sqrt(g² + f² - c).
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions