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In an LR circuit with V = 12 V, R = 4 Ω, L = 2 H, current after t = 0.5 s:
A3 A
B2.5 A
C0.5 A
D1.9 A
Answer & Solution
Correct answer: D. 1.9 A
I = (V/R)(1 - e^(-Rt/L)) = 3(1 - e^(-4 × 0.5/2)) = 3(1 - e⁻¹) = 3 × 0.632 ≈ 1.9 A.
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