alleryIn an LR circuit with V = 12 V, R = 4 Ω, L = 2 H, current after t = 0.5 s:
A3 A
B2.5 A
C0.5 A
D1.9 A
Answer & Solution
Correct answer: D. 1.9 A
We have I = (V/R)(1 - e^(-Rt/L)).
That is I = 3(1 - e^(-4 × 0.5/2)).
That is I = 3(1 - e⁻¹).
So I = 3 × 0.632 ≈ 1.9 A.
Keep practising Electromagnetic Induction
Browse all Electromagnetic Induction questions for JEE Advanced, or explore more Physics topics.
Related questions
Faraday + Lenz — true or false?Inductive reactance increases linearly with frequency. At f = 50 Hz, X_L = 100 Ω. At f = 2Phase difference between voltage and current in pure capacitor in AC:For an AC generator with EMF ε(t) = ε₀ sin(ωt), the RMS EMF:In AC circuit with only inductor, average power consumed over one full cycle:A capacitor C in series with inductor L (LC circuit) oscillates with frequency:Energy density of magnetic field B in vacuum:Two coils with self-inductances L₁ = 4 H, L₂ = 9 H. Maximum possible mutual inductance: