Home › JEE Main › Physics › Electromagnetic Induction › In an LR circuit with V = 12 V, R = 4 Ω, L = 2 H…
In an LR circuit with V = 12 V, R = 4 Ω, L = 2 H, current after t = 0.5 s:
A3 A
B2.5 A
C0.5 A
D1.9 A
Answer & Solution
Correct answer: D. 1.9 A
I = (V/R)(1 - e^(-Rt/L)) = 3(1 - e^(-4 × 0.5/2)) = 3(1 - e⁻¹) = 3 × 0.632 ≈ 1.9 A.
Related questions
The coil of an AC generator connects to the outside circuit through:A coil is labelled 2 H. The H stands for the unit called the:A magnet dropped through an aluminium pipe, compared with a PVC pipe, takes:Some trains brake with electromagnets held above the rails. The braking feels:Cutting slots in the swinging copper plate makes it:A copper plate swings between the poles of a magnet and soon stops. The cause is:A loop moves while lying fully inside a uniform magnetic field. The induced current is:Where does the work you do pushing the magnet into the coil end up?