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Phase difference between voltage and current in pure capacitor in AC:
ACurrent LEADS voltage by 90°
B180°
CVoltage leads by 90°
DIn phase
Answer & Solution
Correct answer: A. Current LEADS voltage by 90°
In capacitor, I = C dV/dt. If V = V₀ sin ωt, then I = ωCV₀ cos ωt = ωCV₀ sin(ωt + π/2). So I leads V by 90°. Mnemonic 'CIVIL': in C, I leads V; in L, V leads I.
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