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Two coils with self-inductances L₁ = 4 H, L₂ = 9 H. Maximum possible mutual inductance:
A36 H
B13 H
C6 H (M_max = sqrt(L₁ L₂))
D2.25 H
Answer & Solution
Correct answer: C. 6 H (M_max = sqrt(L₁ L₂))
M ≤ sqrt(L₁ L₂) = sqrt(36) = 6 H (coupling coefficient k = M/sqrt(L₁ L₂), 0 ≤ k ≤ 1). Maximum when all flux from coil 1 links coil 2.
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