Two coils with self-inductances L₁ = 4 H, L₂ = 9 H. Maximum possible mutual inductance:
A36 H
B13 H
C6 H (M_max = sqrt(L₁ L₂))
D2.25 H
Answer & Solution
Correct answer: C. 6 H (M_max = sqrt(L₁ L₂))
M ≤ sqrt(L₁ L₂) = sqrt(36) = 6 H (coupling coefficient k = M/sqrt(L₁ L₂), 0 ≤ k ≤ 1).
Maximum when all flux from coil 1 links coil 2.
Keep practising Electromagnetic Induction
Browse all Electromagnetic Induction questions for JEE Advanced, or explore more Physics topics.
Related questions
Faraday + Lenz — true or false?Inductive reactance increases linearly with frequency. At f = 50 Hz, X_L = 100 Ω. At f = 2Phase difference between voltage and current in pure capacitor in AC:For an AC generator with EMF ε(t) = ε₀ sin(ωt), the RMS EMF:In AC circuit with only inductor, average power consumed over one full cycle:A capacitor C in series with inductor L (LC circuit) oscillates with frequency:In an LR circuit with V = 12 V, R = 4 Ω, L = 2 H, current after t = 0.5 s:Energy density of magnetic field B in vacuum: