Home › JEE Main › Physics › Electromagnetic Induction › Two coils with self-inductances L₁ = 4 H, L₂ = 9…
Two coils with self-inductances L₁ = 4 H, L₂ = 9 H. Maximum possible mutual inductance:
A36 H
B13 H
C6 H (M_max = sqrt(L₁ L₂))
D2.25 H
Answer & Solution
Correct answer: C. 6 H (M_max = sqrt(L₁ L₂))
M ≤ sqrt(L₁ L₂) = sqrt(36) = 6 H (coupling coefficient k = M/sqrt(L₁ L₂), 0 ≤ k ≤ 1). Maximum when all flux from coil 1 links coil 2.
Related questions
The coil of an AC generator connects to the outside circuit through:A coil is labelled 2 H. The H stands for the unit called the:A magnet dropped through an aluminium pipe, compared with a PVC pipe, takes:Some trains brake with electromagnets held above the rails. The braking feels:Cutting slots in the swinging copper plate makes it:A copper plate swings between the poles of a magnet and soon stops. The cause is:A loop moves while lying fully inside a uniform magnetic field. The induced current is:Where does the work you do pushing the magnet into the coil end up?