Home › JEE Main › Physics › Electromagnetic Induction › Quality factor Q for series LCR at resonance:
Quality factor Q for series LCR at resonance:
AQ = L × C
BQ = R
CQ = ω₀ L / R = (1/R) × sqrt(L/C)
DQ = ω × C
Answer & Solution
Correct answer: C. Q = ω₀ L / R = (1/R) × sqrt(L/C)
Q = ω₀L/R = 1/(ω₀CR) = (1/R)√(L/C). High Q means sharp resonance peak (narrow bandwidth). Used in radio tuning circuits.
Related questions
When a rod moves perpendicular to a magnetic field at constant velocity, the FREE charges An LC circuit oscillates with angular frequency ω equal to:Maxwell's correction to Ampère's law introduced:A bar magnet is dropped through a vertical conducting ring. The magnet:A coil of inductance 0.5 H carries a current changing at 4 A s⁻¹. The induced EMF is:A magnetic flux through a coil changes from 4 Wb to 1 Wb in 0.3 s. The average EMF inducedEddy currents are reduced in transformer cores by:A transformer works on the principle of: