Magnetic flux Φ = B A cos θ. If a coil of area 0.1 m² in B = 0.5 T is rotated from θ=0° to θ=60° in 0.2 s, average EMF:
A0.05 V
B0.5 V
C0.125 V
D0.25 V
Answer & Solution
Correct answer: C. 0.125 V
We have Φ₁ = 0.5 × 0.1 × cos 0.
So Φ₁ = 0.05 Wb.
Φ₂ = 0.5 × 0.1 × cos 60° = 0.025 Wb. ΔΦ = 0.025 Wb.
EMF = |ΔΦ|/Δt = 0.025/0.2 = 0.125 V.
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