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Faraday's first law of electrolysis states mass deposited is proportional to:
AVoltage only
BQuantity of charge (Q = I × t)
CTime only
DResistance
Answer & Solution
Correct answer: B. Quantity of charge (Q = I × t)
Faraday's 1st law: m ∝ Q = I × t. Specifically m = (Q × M) / (n × F) where M is molar mass, n is electrons per mole of product, F is Faraday's constant.
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