During electrolysis of **aqueous** NaCl (brine), the products are:
AH₂ at cathode, Cl₂ at anode, NaOH in solution
BNa, Cl₂, H₂
CNaH, O₂, water
DNa at cathode, O₂ at anode
Answer & Solution
Correct answer: A. H₂ at cathode, Cl₂ at anode, NaOH in solution
**Aqueous NaCl (chlor-alkali):** water reduces in preference to Na⁺ (E°(H₂O) > E°(Na⁺) so H₂ at cathode + OH⁻ formed → NaOH).
At anode Cl⁻ oxidises in preference to water due to **overpotential on oxygen** → Cl₂ gas.
Keep practising Unit 9B1: Electrochemical Cells and Standard Potentials
Browse all Unit 9B1: Electrochemical Cells and Standard Potentials questions for AP Intermediate 2nd Year, or explore more Chemistry topics.
Related questions
Faraday's first law of electrolysis states mass deposited is proportional to:EMF of standard Daniell cell at 25°C is approximately:In the Daniell cell, the cathode reaction is:A device converting CHEMICAL energy to electrical energy via spontaneous redox is a:In the H₂–O₂ fuel cell used in the Apollo space programme, the electrolyte is:A CuSO₄ solution is electrolysed with 1.5 A for 10 minutes. The mass of copper (M = 63.5) The Faraday constant F = 96500 C mol⁻¹ represents:Given Λ°_m for HCl, NaAc, NaCl = 425.9, 91.0, 126.4 S cm² mol⁻¹ respectively. Calculate Λ°