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Given Λ°_m for HCl, NaAc, NaCl = 425.9, 91.0, 126.4 S cm² mol⁻¹ respectively. Calculate Λ°_m for acetic acid (HAc):
A643.3
B390.5
C491.5
D425.9
Answer & Solution
Correct answer: B. 390.5
Λ°_m(HAc) = Λ°_m(HCl) + Λ°_m(NaAc) − Λ°_m(NaCl) = 425.9 + 91.0 − 126.4 = **390.5 S cm² mol⁻¹**. Method exploits Kohlrausch to get Λ° for a weak electrolyte that cannot be obtained directly from extrapolation.
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