The angular momentum L of the electron in the n-th Bohr orbit is:
An h
Bn h/π
Cn h/(2π)
Dn²h
Answer & Solution
Correct answer: C. n h/(2π)
We have L = n ħ.
So L = n h/(2π).
Keep practising Modern Physics
Browse all Modern Physics questions for NEET UG, or explore more Physics topics.
Related questions
True or false: modern physicsMatch each photoelectric termFor the ground state of singly ionised helium (He⁺, Z = 2), the energy of the electron is:The de Broglie wavelength of an electron in the n = 1 Bohr orbit of hydrogen equals the:In Bohr's model, the centripetal force on the electron is supplied by the:The energy required to excite a hydrogen atom from the ground state to its first excited sNumber of spectral lines emitted when a hydrogen atom de-excites from n = 4 to n = 1 (all The wavelength of a photon emitted when an electron in hydrogen jumps from n = 3 to n = 2