For the ground state of singly ionised helium (He⁺, Z = 2), the energy of the electron is:
A−54.4 eV
B−27.2 eV
C−13.6 eV
D−108.8 eV
Answer & Solution
Correct answer: A. −54.4 eV
E = −13.6 Z²/n² = −13.6·4/1 = −54.4 eV.
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