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A 100 W, 220 V bulb has resistance (when operating):

A100 Ω
B220 Ω
C22 Ω
D484 Ω
Answer & Solution
Correct answer: D. 484 Ω
We have R = V²/P. That is R = 220²/100. That is R = 48400/100. So R = 484 Ω.
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