What frictional force lets a 1,000 kg car round a 20 m radius curve at 30 m/s without sliding?
A22.0 N
B667 N
C1500 N
D45000 N
Answer & Solution
Correct answer: D. 45000 N
1. Friction supplies the centripetal force: f = m v^2 / r.
2. f = (1,000 kg)(30 m/s)^2 / 20 m = (1,000)(900) / 20.
3. f = 900,000 / 20 = 45,000 N.
_Source: OpenStax Physics (CC BY 4.0), Ch 6 "Circular and Rotational Motion", section 6.2 Uniform Circular Motion_
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