An object's angular acceleration is 36 rad/s^2 and it starts at an angular velocity of 6.0 rad/s. What is its angular velocity after 5.0 s?
A30 rad/s
B42 rad/s
C150 rad/s
D186 rad/s
Answer & Solution
Correct answer: D. 186 rad/s
1. omega = omega_0 + alpha t.
2. omega = 6.0 rad/s + (36 rad/s^2)(5.0 s) = 6.0 + 180.
3. omega = 186 rad/s.
_Source: OpenStax Physics (CC BY 4.0), Ch 6 "Circular and Rotational Motion", section 6.3 Rotational Motion_
Keep practising Circular and Rotational Motion
Browse all Circular and Rotational Motion questions for NCEA Level 3, or explore more Physics topics.
Related questions
A fan is switched on and undergoes an angular acceleration of 150 rad/s^2 from rest. How lAn object's angular velocity changes from 3 rad/s clockwise to 8 rad/s clockwise over 5 s.A person applies a 12 N force 1.0 m from a pivot point, perpendicular to the lever arm. HoFor a given force, how should it be applied to a lever arm to maximize the torque producedWhat is the lever arm, in the definition of torque?What is torque, in physical terms?By the convention used for angular acceleration's sign, which direction of rotation countsHow is angular acceleration defined?