alleryStart learning →A clock has a radius of 0.5 m. What is the tangential speed of the outermost point on its minute hand?
A8.5 x 10^-2 m/s
B3.4 x 10^-3 m/s
C9 x 10^-4 m/s
D1.3 x 10^1 m/s
Answer & Solution
Correct answer: C. 9 x 10^-4 m/s
1. The minute hand completes 2pi rad every 60 minutes, or 3600 s.
2. omega = 2pi / 3600 s = 1.75 x 10^-3 rad/s.
3. v = r omega = (0.5 m)(1.75 x 10^-3 rad/s) = 8.7 x 10^-4 m/s, which rounds to 9 x 10^-4 m/s.
_Source: OpenStax Physics (CC BY 4.0), Ch 6 "Circular and Rotational Motion", section 6.1 Angle of Rotation and Angular Velocity_
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