Using n1 equals 1.333 for water and n2 equals 1.0003 for air, what critical angle does theta_c equals the inverse sine of n2 over n1 give for light travelling from water into air?

1. The critical angle formula is theta_c = inverse sine of (n2 / n1), valid when n1 is the larger index. 2. Here n1 = 1.333 for water and n2 = 1.0003 for air, so n2 / n1 = 1.0003 / 1.333 = 0.7504. 3. Taking the inverse sine of 0.7504 gives theta_c = 48.6 degrees. 4. 24.4 degrees is the critical angle for diamond and air, a different pair of materials entirely. 5. 90.0 degrees would only occur if n2 equalled n1, which is not the case for water and air. 6. 41.8 degrees does not match the inverse sine of the computed ratio. _Source: OpenStax Physics (CC BY 4.0), Ch 16 "Mirrors and Lenses", section 16.2 Refraction_