A book page is held 6.50 cm from a concave lens whose focal length is -10.0 cm. Using d_i equals f d_o over (d_o minus f), what image distance and magnification result?

1. Using d_i = (f d_o) / (d_o - f) = ((-10.0)(6.50)) / (6.50 - (-10.0)) = -65.0 / 16.5 = -3.94 cm. 2. The negative image distance means the image is virtual, on the same side of the lens as the object. 3. Magnification is m = -d_i / d_o = -(-3.94) / 6.50 = 0.606. 4. A positive magnification means the image is upright, and a magnitude less than one means it is smaller than the object. 5. d_i = 3.94 cm would wrongly make the image real, which a diverging lens on its own cannot produce. 6. A magnitude like 2.54 does not follow from substituting these values, and negative magnification here would wrongly flip the image upside down. _Source: OpenStax Physics (CC BY 4.0), Ch 16 "Mirrors and Lenses", section 16.3 Lenses_