A light bulb sits 0.75 m from a convex lens with a 0.50 m focal length. Using d_i equals f d_o over (d_o minus f), what image distance and magnification result?

1. Using d_i = (f d_o) / (d_o - f) = ((0.50)(0.75)) / (0.75 - 0.50) = 0.375 / 0.25 = 1.5 m. 2. The positive image distance means the image is real, formed on the far side of the lens from the object. 3. Magnification is m = -d_i / d_o = -1.5 / 0.75 = -2.0. 4. A negative magnification means the image is inverted, and a magnitude greater than one means it is enlarged. 5. d_i = -1.5 m would wrongly make the image virtual, which cannot happen when the object sits beyond the focal length of a converging lens. 6. d_i = 0.30 m does not follow from substituting these object distance and focal length values into the equation. _Source: OpenStax Physics (CC BY 4.0), Ch 16 "Mirrors and Lenses", section 16.3 Lenses_