An 8.0 cm tall object sits 6.0 cm from a concave mirror that produces a magnification of -2.0. Using m equals h_i over h_o equals negative d_i over d_o, what are the image height and image distance?

1. Image height comes from m = h_i / h_o, so h_i = m h_o = (-2.0)(8.0 cm) = -16 cm. 2. The negative sign on h_i means the image is inverted compared with the upright 8.0 cm object. 3. Image distance comes from m = -d_i / d_o, so d_i = -m d_o = -(-2.0)(6.0 cm) = 12 cm. 4. The positive sign on d_i means the image is real, formed in front of the mirror. 5. h_i = 16 cm would wrongly make the image upright, ignoring the negative magnification that flips its orientation. 6. d_i = -12 cm would wrongly make the image virtual, which cannot happen when magnification is negative and greater than one in size. _Source: OpenStax Physics (CC BY 4.0), Ch 16 "Mirrors and Lenses", section 16.1 Reflection_