A guitar string 0.600 m long is fixed at both ends, and waves travel along it at 240 m/s. What is its fundamental frequency?

1. For a string fixed at both ends, the fundamental wavelength is twice the length. 2. wavelength = 2 x 0.600 m = 1.20 m. 3. Frequency comes from f = v_w / wavelength. 4. f = 240 m/s divided by 1.20 m = 200 Hz. 5. Using the string length itself as the wavelength gives 400 Hz, which is the next pattern up rather than the fundamental. 6. Multiplying 240 by 0.600 gives 144, which is neither a frequency nor a length. _Source: OpenStax College Physics (CC BY 4.0), Ch 16 "Oscillatory Motion and Waves", section Standing Waves_