A speaker sends 1.50 W of sound power evenly through an opening of area 0.0150 m squared. What is the intensity of the sound there?

1. Intensity is I = P / A. 2. Substitute: I = 1.50 W divided by 0.0150 m squared. 3. I = 100 W/m squared. 4. Dividing area by power instead gives 0.0100, which inverts the definition. 5. Multiplying power by area gives 0.0225, whose units are watt square meters and mean nothing here. _Source: OpenStax College Physics (CC BY 4.0), Ch 16 "Oscillatory Motion and Waves", section 16.11 Energy in Waves: Intensity_