That 500 A flows through transmission lines of total resistance 1.00 ohm. What power is dissipated in the lines?

1. Loss in a line of known resistance carrying a known current is P = I squared R. 2. Square the current: (500 A) squared = 250000 A squared. 3. Multiply by the line resistance: P = (250000 A squared)(1.00 ohm) = 250000 W. 4. In convenient units that is 250 kW. 5. Compared with the 100 MW being carried, that is a loss of 0.250 percent. 6. 500 kW would follow from using P = I V with the line resistance mistaken for a voltage. 7. 125 kW halves the correct figure and would follow from squaring 250 A rather than 500 A. _Source: OpenStax College Physics (CC BY 4.0), Ch 20 "Electric Current, Resistance, and Ohm's Law", section Why Use AC for Power Distribution?_