alleryStart learning →An AC light bulb has an average power consumption of 60.0 W. What is its peak power?
A30.0 W
B60.0 W
C120 W
D170 W
Answer & Solution
Correct answer: C. 120 W
1. Peak power is peak current times peak voltage, P_0 = I_0 V_0.
2. Average power for a resistive AC load is P_ave = one half of I_0 V_0.
3. Comparing the two gives P_0 = 2 P_ave.
4. Substituting: P_0 = 2 (60.0 W) = 120 W.
5. The power therefore swings between zero and 120 W twice in each cycle while averaging 60 W.
_Source: OpenStax College Physics (CC BY 4.0), Ch 20 "Electric Current, Resistance, and Ohm's Law", section Alternating Current_
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