Reading P = V squared / R for a fixed supply voltage, what happens as the connected resistance falls?

1. In P = V squared / R the resistance sits in the denominator. 2. Holding V fixed and shrinking R therefore makes P larger. 3. So the lower the resistance connected across a given supply, the greater the power delivered. 4. This is why a near-zero resistance path across a supply dissipates a dangerous amount of power. 5. Option four inverts the dependence and would predict that a short circuit is harmless. _Source: OpenStax College Physics (CC BY 4.0), Ch 20 "Electric Current, Resistance, and Ohm's Law", section Power in Electric Circuits_