Power dissipated in a resistor R carrying current I is:
AP = I R
BP = I R²
CP = I² R
DP = I / R²
Answer & Solution
Correct answer: C. P = I² R
1. P = V I = (I R) · I = I² R.
2. Equivalent forms: P = V² / R = V I.
3. All energy dissipated appears as heat (Joule heating).
_Source: NCERT Class 12 Physics Ch 3 §3.6 Electrical Energy and Power_
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