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In an ideal gas that process leaves internal energy unchanged, so all the heat supplied goes into:
AWater vapour
BWork done out
CWasted mass
DWall thickness
Answer & Solution
Correct answer: B. Work done out
1. Internal energy depends only on temperature, which is constant.
2. The first law then makes heat in equal work out.
3. All the heat supplied goes into work done out by the gas.
_Source: OpenStax University Physics Volume 2, Chapter 3, The First Law of Thermodynamics._
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