Home › Kerala SSLC (Class 10) › Mathematics › Pyramids › Continuing the tent problem (base 6 m, height 4 …
Continuing the tent problem (base 6 m, height 4 m, slant height 5 m), the area of canvas needed for the four triangular faces is:
A15 m²
B30 m²
C45 m²
D60 m²
Answer & Solution
Correct answer: D. 60 m²
1. Each triangular face has area (1/2)(6)(5) = 15 m².
2. There are four such faces in a square pyramid tent.
3. Total canvas area = 4 × 15 = 60 m².
4. The base is open ground in a tent, so it does not consume canvas.
5. So 60 m² of canvas is required.
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 7-8 (pp 180-199, 2019 ed.)._
Related questions
In any square pyramid, which of the following squared quantities are in arithmetic progresThe Great Pyramid of Giza in Egypt has a roughly square base with side close to half a lakAll edges of a square pyramid are 18 cm (base edges and lateral edges both 18 cm). Its slaTwo square pyramids have equal volumes. The base edge of one is half the base edge of the A metal cube of edge 15 cm is melted and recast into a square pyramid with base edge 25 cmThe volume of a square pyramid of base edge 10 cm and vertical height 8 cm equals:A tent in the shape of a square pyramid has base edges 6 m and vertical height 4 m. The slIn a square pyramid the pyramid's vertical height h, slant height l and half the base edge