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In a square pyramid the pyramid's vertical height h, slant height l and half the base edge a/2 are related by which equation?
Ah² = l² + (a/2)²
Bl² = h² + (a/2)²
C(a/2)² = l² + h²
Dl = h + a/2
Answer & Solution
Correct answer: B. l² = h² + (a/2)²
1. Drop a perpendicular from the apex to the centre of the base. Its length is h.
2. From the centre of the base to the midpoint of one base edge is a/2.
3. From the midpoint of the base edge up to the apex (along a triangular face) is the slant height l.
4. These three lengths form a right triangle with l as hypotenuse.
5. So l² = h² + (a/2)².
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 7-8 (pp 180-199, 2019 ed.)._
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