The value of $\sin 0^{\circ} + \cos 0^{\circ} + \tan 45^{\circ}$ is:
A$1$
B$2$
C$3$
D$0$
Answer & Solution
Correct answer: B. $2$
$\sin 0^{\circ} = 0$, $\cos 0^{\circ} = 1$, $\tan 45^{\circ} = 1$. Sum: $0 + 1 + 1 = 2$.
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