The value of $\sin 0^{\circ} + \cos 0^{\circ} + \tan 45^{\circ}$ is:
A$1$
B$2$
C$3$
D$0$
Answer & Solution
Correct answer: B. $2$
$\sin 0^{\circ} = 0$, $\cos 0^{\circ} = 1$, $\tan 45^{\circ} = 1$. Sum: $0 + 1 + 1 = 2$.
Related questions
Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE For [[1,2],[2,4]], the determinant equals:If A is invertible, |A^{−1}| equals:For a 3 × 3 non-singular A with |A| = 5, the value of |adj A| is:For a non-singular square matrix A of order n, |adj A| equals:For non-singular A, B of the same order, (AB)^{−1} equals:For a non-singular A, (A^{−1})^{−1} equals: