sin(2nπ + x) equals (for any integer n):
Acos x
Bsin(x + π)
C-sin x
Dsin x
Answer & Solution
Correct answer: D. sin x
Sine has period 2π. Adding any integer multiple of 2π brings you back to the same point on the unit circle. So sin(2nπ + x) = sin x for any n ∈ ℤ.
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