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At which of the following x-values is cos x equal to zero?
Ax = (2n+1)π/2
Bx = nπ
Cx = 2nπ
Dx = 2nπ + π/3
Answer & Solution
Correct answer: A. x = (2n+1)π/2
cos x = 0 at odd multiples of π/2 (i.e. ±π/2, ±3π/2, ...). General form: x = (2n+1)π/2, n ∈ ℤ. (sin x = 0 at x = nπ — option A is the wrong function.)
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