What is the value of $\cos 60^{\circ}$?
A$\dfrac{1}{2}$
B$\dfrac{\sqrt{3}}{2}$
C$0$
D$1$
Answer & Solution
Correct answer: A. $\dfrac{1}{2}$
$\cos 60^{\circ} = \dfrac{1}{2}$. (Note $\sin 30^{\circ} = \cos 60^{\circ}$ — complementary angles.)
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